Kode #4: hints & solution
Here's the clue board for Kode #4. Start with the spoiler-free hints. If you're still stuck, the full step-by-step solution is below, hidden until you open it.
The clue board
Each row is a guess that's already been graded. ▲ means a right digit in the right spot; ● means a right digit in the wrong spot.
- 11490▲1●1
- 21230▲0●1
- 31795▲0●2
- 46708▲0●0
- 53740▲0●2
Spoiler-free hints
- Exactly one of the four digits is even.
- The four digits add up to 21.
- 2 of the digits are 5 or higher.
Try the hints first. The solution below walks through every deduction.
Step-by-step solution
Every Kode can be cracked by pure deduction, with no guessing. This board falls in 9 logical steps. Open the solution to follow them one at a time.
Show the solution · reveals the code
When a row "rules out" a position, it shows that digit there but its ▲ marks are already used up (or it has none), so the digit can't sit there.
- Row 4 (6 7 0 8) has no marks at all, so 6, 7, 0, and 8 are not in the code.
- Row 5 (3 7 4 0) has 2 marks still unexplained, and only 2 digits are left undecided: 3 and 4. So both are in the code.
- Row 2 (1 2 3 0) has one mark, already accounted for by 3. That rules out 1 and 2.
- Row 1 (1 4 9 0) has one mark still unexplained, and only one digit is left undecided: 9. So it is in the code.
- Row 3 (1 7 9 5) has one mark still unexplained, and only one digit is left undecided: 5. So it is in the code.
- Row 1 (1 4 9 0) has one digit in the right spot. Since row 3 rules out the 9 in position 3, it has to be the 4 in position 2.
- The 3 has only one spot left: position 4 (row 5 rules out position 1, row 2 rules out position 3, and position 2 is already 4).
- The 9 has only one spot left: position 1 (row 3 rules out position 3, position 2 is already 4, and position 4 is already 3).
- That leaves the 5 for position 3.
That cracks it: the code is 9453.