Kode #3: hints & solution
Here's the clue board for Kode #3. Start with the spoiler-free hints. If you're still stuck, the full step-by-step solution is below, hidden until you open it.
The clue board
Each row is a guess that's already been graded. ▲ means a right digit in the right spot; ● means a right digit in the wrong spot.
- 16490▲1●1
- 26398▲0●1
- 31904▲1●1
- 46751▲0●3
- 54827▲0●0
Spoiler-free hints
- 2 of the four digits are even.
- The four digits add up to 12.
- 2 of the digits are 5 or higher.
Try the hints first. The solution below walks through every deduction.
Step-by-step solution
Every Kode can be cracked by pure deduction, with no guessing. This board falls in 8 logical steps. Open the solution to follow them one at a time.
Show the solution · reveals the code
When a row "rules out" a position, it shows that digit there but its ▲ marks are already used up (or it has none), so the digit can't sit there.
- Row 5 (4 8 2 7) has no marks at all, so 4, 8, 2, and 7 are not in the code.
- Row 4 (6 7 5 1) has 3 marks still unexplained, and only 3 digits are left undecided: 6, 5, and 1. So all of them are in the code.
- Row 2 (6 3 9 8) has one mark, already accounted for by 6. That rules out 3 and 9.
- Row 1 (6 4 9 0) has one mark still unexplained, and only one digit is left undecided: 0. So it is in the code.
- Row 1 (6 4 9 0) has one digit in the right spot. Since row 2 rules out the 6 in position 1, it has to be the 0 in position 4.
- Row 3 (1 9 0 4) has one digit in the right spot. Since the 0 is already in position 4, it has to be the 1 in position 1.
- The 5 has only one spot left: position 2 (row 4 rules out position 3, position 1 is already 1, and position 4 is already 0).
- That leaves the 6 for position 3.
That cracks it: the code is 1560.