Kode #87: hints & solution
Here's the clue board for Kode #87. Start with the spoiler-free hints. If you're still stuck, the full step-by-step solution is below, hidden until you open it.
The clue board
Each row is a guess that's already been graded. ▲ means a right digit in the right spot; ● means a right digit in the wrong spot.
- 14671▲1●1
- 27651▲0●2
- 30526▲0●2
- 42689▲0●0
- 59412▲0●2
Spoiler-free hints
- 2 of the four digits are even.
- The four digits add up to 10.
- Just one digit is 5 or higher.
Try the hints first. The solution below walks through every deduction.
Step-by-step solution
Every Kode can be cracked by pure deduction, with no guessing. This board falls in 9 logical steps. Open the solution to follow them one at a time.
Show the solution · reveals the code
When a row "rules out" a position, it shows that digit there but its ▲ marks are already used up (or it has none), so the digit can't sit there.
- Row 4 (2 6 8 9) has no marks at all, so 2, 6, 8, and 9 are not in the code.
- Row 3 (0 5 2 6) has 2 marks still unexplained, and only 2 digits are left undecided: 0 and 5. So both are in the code.
- Row 5 (9 4 1 2) has 2 marks still unexplained, and only 2 digits are left undecided: 4 and 1. So both are in the code.
- Row 1 (4 6 7 1) has 2 marks, already accounted for by 4 and 1. That rules out 7.
- That makes all four digits of the code: 0, 1, 4, and 5. Every other digit is out, which also rules out 3.
- Row 1 (4 6 7 1) has one digit in the right spot. Since row 2 rules out the 1 in position 4, it has to be the 4 in position 1.
- The 1 has only one spot left: position 2 (row 5 rules out position 3, row 2 rules out position 4, and position 1 is already 4).
- The 5 has only one spot left: position 4 (row 2 rules out position 3, position 1 is already 4, and position 2 is already 1).
- That leaves the 0 for position 3.
That cracks it: the code is 4105.