Kode #71: hints & solution
Here's the clue board for Kode #71. Start with the spoiler-free hints. If you're still stuck, the full step-by-step solution is below, hidden until you open it.
The clue board
Each row is a guess that's already been graded. ▲ means a right digit in the right spot; ● means a right digit in the wrong spot.
- 11208▲1●1
- 21902▲0●2
- 30521▲1●1
- 48063▲1●1
- 50754▲0●0
Spoiler-free hints
- 2 of the four digits are even.
- The four digits add up to 12.
- Just one digit is 5 or higher.
Try the hints first. The solution below walks through every deduction.
Step-by-step solution
Every Kode can be cracked by pure deduction, with no guessing. This board falls in 9 logical steps. Open the solution to follow them one at a time.
Show the solution · reveals the code
When a row "rules out" a position, it shows that digit there but its ▲ marks are already used up (or it has none), so the digit can't sit there.
- Row 5 (0 7 5 4) has no marks at all, so 0, 7, 5, and 4 are not in the code.
- Row 3 (0 5 2 1) has 2 marks still unexplained, and only 2 digits are left undecided: 2 and 1. So both are in the code.
- Row 1 (1 2 0 8) has 2 marks, already accounted for by 1 and 2. That rules out 8.
- Row 2 (1 9 0 2) has 2 marks, already accounted for by 1 and 2. That rules out 9.
- Row 4 (8 0 6 3) has 2 marks still unexplained, and only 2 digits are left undecided: 6 and 3. So both are in the code.
- Row 1 (1 2 0 8) has one digit in the right spot. Since row 2 rules out the 1 in position 1, it has to be the 2 in position 2.
- Row 3 (0 5 2 1) has one digit in the right spot. Since the 2 is already in position 2, it has to be the 1 in position 4.
- Row 4 (8 0 6 3) has one digit in the right spot. Since position 4 is already 1, it has to be the 6 in position 3.
- That leaves the 3 for position 1.
That cracks it: the code is 3261.