Kode #55: hints & solution
Here's the clue board for Kode #55. Start with the spoiler-free hints. If you're still stuck, the full step-by-step solution is below, hidden until you open it.
The clue board
Each row is a guess that's already been graded. ▲ means a right digit in the right spot; ● means a right digit in the wrong spot.
- 15124▲1●1
- 29724▲0●1
- 34896▲0●2
- 43406▲0●2
- 53196▲0●0
Spoiler-free hints
- 3 of the four digits are even.
- The four digits add up to 17.
- 2 of the digits are 5 or higher.
Try the hints first. The solution below walks through every deduction.
Step-by-step solution
Every Kode can be cracked by pure deduction, with no guessing. This board falls in 9 logical steps. Open the solution to follow them one at a time.
Show the solution · reveals the code
When a row "rules out" a position, it shows that digit there but its ▲ marks are already used up (or it has none), so the digit can't sit there.
- Row 5 (3 1 9 6) has no marks at all, so 3, 1, 9, and 6 are not in the code.
- Row 3 (4 8 9 6) has 2 marks still unexplained, and only 2 digits are left undecided: 4 and 8. So both are in the code.
- Row 2 (9 7 2 4) has one mark, already accounted for by 4. That rules out 7 and 2.
- Row 1 (5 1 2 4) has one mark still unexplained, and only one digit is left undecided: 5. So it is in the code.
- Row 4 (3 4 0 6) has one mark still unexplained, and only one digit is left undecided: 0. So it is in the code.
- Row 1 (5 1 2 4) has one digit in the right spot. Since row 2 rules out the 4 in position 4, it has to be the 5 in position 1.
- The 4 has only one spot left: position 3 (row 4 rules out position 2, row 2 rules out position 4, and position 1 is already 5).
- The 8 has only one spot left: position 4 (row 3 rules out position 2, position 1 is already 5, and position 3 is already 4).
- That leaves the 0 for position 2.
That cracks it: the code is 5048.