Kode #193: hints & solution
Here's the clue board for Kode #193. Start with the spoiler-free hints. If you're still stuck, the full step-by-step solution is below, hidden until you open it.
Play Kode #193The clue board
Each row is a guess that's already been graded. ▲ means a right digit in the right spot; ● means a right digit in the wrong spot.
- 14091▲1●1
- 28021▲0●1
- 33850▲0●2
- 47603▲0●1
- 54270▲0●0
Spoiler-free hints
- All four digits are odd.
- The four digits add up to 18.
- 2 of the digits are 5 or higher.
Try the hints first. The solution below walks through every deduction.
Step-by-step solution
Every Kode can be cracked by pure deduction, with no guessing. This board falls in 9 logical steps. Open the solution to follow them one at a time.
Show the solution · reveals the code
When a row "rules out" a position, it shows that digit there but its ▲ marks are already used up (or it has none), so the digit can't sit there.
- Row 5 (4 2 7 0) has no marks at all, so 4, 2, 7, and 0 are not in the code.
- Row 1 (4 0 9 1) has 2 marks still unexplained, and only 2 digits are left undecided: 9 and 1. So both are in the code.
- Row 2 (8 0 2 1) has one mark, already accounted for by 1. That rules out 8.
- Row 3 (3 8 5 0) has 2 marks still unexplained, and only 2 digits are left undecided: 3 and 5. So both are in the code.
- Row 4 (7 6 0 3) has one mark, already accounted for by 3. That rules out 6.
- Row 1 (4 0 9 1) has one digit in the right spot. Since row 2 rules out the 1 in position 4, it has to be the 9 in position 3.
- The 3 has only one spot left: position 2 (row 3 rules out position 1, row 4 rules out position 4, and position 3 is already 9).
- The 1 has only one spot left: position 1 (row 2 rules out position 4, position 2 is already 3, and position 3 is already 9).
- That leaves the 5 for position 4.
That cracks it: the code is 1395.