Kode #183: hints & solution
Here's the clue board for Kode #183. Start with the spoiler-free hints. If you're still stuck, the full step-by-step solution is below, hidden until you open it.
The clue board
Each row is a guess that's already been graded. ▲ means a right digit in the right spot; ● means a right digit in the wrong spot.
- 18920▲1●1
- 28123▲0●1
- 33254▲0●2
- 48071▲0●0
- 55306▲0●2
Spoiler-free hints
- 2 of the four digits are even.
- The four digits add up to 22.
- 3 of the digits are 5 or higher.
Try the hints first. The solution below walks through every deduction.
Step-by-step solution
Every Kode can be cracked by pure deduction, with no guessing. This board falls in 9 logical steps. Open the solution to follow them one at a time.
Show the solution · reveals the code
When a row "rules out" a position, it shows that digit there but its ▲ marks are already used up (or it has none), so the digit can't sit there.
- Row 4 (8 0 7 1) has no marks at all, so 8, 0, 7, and 1 are not in the code.
- Row 1 (8 9 2 0) has 2 marks still unexplained, and only 2 digits are left undecided: 9 and 2. So both are in the code.
- Row 2 (8 1 2 3) has one mark, already accounted for by 2. That rules out 3.
- Row 5 (5 3 0 6) has 2 marks still unexplained, and only 2 digits are left undecided: 5 and 6. So both are in the code.
- Row 3 (3 2 5 4) has 2 marks, already accounted for by 2 and 5. That rules out 4.
- Row 1 (8 9 2 0) has one digit in the right spot. Since row 2 rules out the 2 in position 3, it has to be the 9 in position 2.
- The 5 has only one spot left: position 4 (row 5 rules out position 1, row 3 rules out position 3, and position 2 is already 9).
- The 2 has only one spot left: position 1 (row 2 rules out position 3, position 2 is already 9, and position 4 is already 5).
- That leaves the 6 for position 3.
That cracks it: the code is 2965.