Kode #128: hints & solution
Here's the clue board for Kode #128. Start with the spoiler-free hints. If you're still stuck, the full step-by-step solution is below, hidden until you open it.
The clue board
Each row is a guess that's already been graded. ▲ means a right digit in the right spot; ● means a right digit in the wrong spot.
- 11625▲1●1
- 27425▲0●1
- 39540▲0●2
- 40748▲0●0
- 54813▲1●1
Spoiler-free hints
- All four digits are odd.
- The four digits add up to 18.
- 2 of the digits are 5 or higher.
Try the hints first. The solution below walks through every deduction.
Step-by-step solution
Every Kode can be cracked by pure deduction, with no guessing. This board falls in 9 logical steps. Open the solution to follow them one at a time.
Show the solution · reveals the code
When a row "rules out" a position, it shows that digit there but its ▲ marks are already used up (or it has none), so the digit can't sit there.
- Row 4 (0 7 4 8) has no marks at all, so 0, 7, 4, and 8 are not in the code.
- Row 3 (9 5 4 0) has 2 marks still unexplained, and only 2 digits are left undecided: 9 and 5. So both are in the code.
- Row 2 (7 4 2 5) has one mark, already accounted for by 5. That rules out 2.
- Row 5 (4 8 1 3) has 2 marks still unexplained, and only 2 digits are left undecided: 1 and 3. So both are in the code.
- Row 1 (1 6 2 5) has 2 marks, already accounted for by 1 and 5. That rules out 6.
- Row 1 (1 6 2 5) has one digit in the right spot. Since row 2 rules out the 5 in position 4, it has to be the 1 in position 1.
- Row 5 (4 8 1 3) has one digit in the right spot. Since the 1 is already in position 1, it has to be the 3 in position 4.
- The 5 has only one spot left: position 3 (row 3 rules out position 2, position 1 is already 1, and position 4 is already 3).
- That leaves the 9 for position 2.
That cracks it: the code is 1953.